Question

can someone help me with this?
lim(2x+1) / (x-2), x ->infinity

thank you

Answer 1

\[\lim_{x\to\infty}\frac{2x+1}{x-2}\]
Divide through by the highest power of \(x\):
\[\displaystyle\lim_{x\to\infty}\dfrac{2+\dfrac{1}{x}}{1-\dfrac{2}{x}}\]
What happens to the fractions as \(x\to\infty\)?

Answer 2

tends to 2.
Thank you! I have too much to learn. 8)

Answer 3

tends to 0, I mean.
Thank you.