Question

differentiation of logarithmic functions.

Answer 1

some smart fancy words.....................

Answer 2

\[2x \log_{}\sqrt x\]

Answer 3

started by using the product rule --> (2x)(logsqrtx)

Answer 4

Yeah you can do that, product rule
\[y'=udv+vdu\]
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\[u=2x\]
\[v=\log(\sqrt{x})\]
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\[\Large y'=2x\frac{1}{\sqrt{x}}(\frac{1}{2\sqrt{x}})+2\log(\sqrt{x})\]