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OpenStudy (anonymous):
Simplify 15C3.
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OpenStudy (anonymous):
U know the formula for finding number of combinations?
OpenStudy (anonymous):
15C3 is simply 15*14*13/3*2*1 = 5*7*13 n!/(n-r)!r!
OpenStudy (anonymous):
Ah... that makes sense. Thanks!
OpenStudy (anonymous):
:D welcome :D and thanks
OpenStudy (anonymous):
Of course! :)
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