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Mathematics 22 Online
OpenStudy (anonymous):

Simplify 15C3.

OpenStudy (anonymous):

U know the formula for finding number of combinations?

OpenStudy (anonymous):

15C3 is simply 15*14*13/3*2*1 = 5*7*13 n!/(n-r)!r!

OpenStudy (anonymous):

Ah... that makes sense. Thanks!

OpenStudy (anonymous):

:D welcome :D and thanks

OpenStudy (anonymous):

Of course! :)

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