Question

if sin y= 9/c and tan y= 9/d what is cos y?

Answer 1

Hint:

tan(y) = sin(y)/cos(y)

Answer 2

@jim_thompson5910 @Hero would it be cos y= d/c

Answer 3

tan(y) = sin(y)/cos(y)

9/d = (9/c)/cos(y)

cos(y)*9/d = 9/c

cos(y) = (9/c)/(9/d)

cos(y) = (9/c)*(d/9)

cos(y) = d/c

Answer 4

so you got it