Question

y/2y+4 - 3/x+2.

Answer 1

you got \(x\)'s and \(y\)'s ?

Answer 2

Yes

Answer 3

such as y = x2 or y = 3x + 1

Answer 4

Y 3
-------- MINUS --------
2y + 4 x+2

Answer 5

\[\frac{y}{2y+4}-\frac{3}{x+2}\]\[=\frac{y(x+2)-3(2y+4)}{(2y+4)(x+2)}\] as a start

Answer 6

wuts y

Answer 7

then multiply out in the numerator and that will be all

Answer 8

\[=\frac{y(x+2)-3(2y+4)}{(2y+4)(x+2)}\]
\[=\frac{xy+2y-6y-12}{(2y+4)(x+2)}=\frac{xy-4y-12}{(2y+4)(x+2)}\]