Question

Find the standard form.
Center at origin (0,0); passes through (6,-7)

Answer 1

circle?

Answer 2

yes

Answer 3

if the center is \((0,0)\) you know it is going to look like \(x^2+y^2=r^2\) where \(r^2\) is the square of the distance between \((0,0)\) and \((6,-7)\)

Answer 4

in other words, \(r^2=6^2+7^2\)

Answer 5

thank you!

Answer 6

yw