Question

find the limit

lim x approaches a x-1/sqrt. 2x=x^2-1

Answer 1

\[\lim_{x \rightarrow a} \frac{ x-1 }{ \sqrt{2x-x^2-1} }\]

Answer 2

Take Limit in use, with the fabonacci Summation

Answer 3

a=1negative

Answer 4

help

Answer 5

ya correct.

Answer 6

\[\large \lim_{x\to 1^{-}} \frac{(x-1) }{\sqrt{-x^2+2 x-1}}\]

Answer 7

i work on this so far, whatt will be the next?\[\frac{ \sqrt{(x-1)^2} }{ -\sqrt{(x-1)(x-)}}\]

Answer 8

Try factor it
\[\frac{a-1}{\sqrt{-1}\sqrt{(a-1)^2}} \\ \\ \frac{a-1}{i(a-1)}\]

Answer 9

i?

Answer 10

ok thanks