12x^2-8x-7=0 solve.

Question

12x^2-8x-7=0 solve.

hunus · Answer

Well we know that the first number (12x^2) when factored (if it's factorable) has to have two values of x whose coefficients multiply to equal 12.

These can be

1 * 12
2 * 6
3 * 4

the last number (7) can only be made up by two numbers multiplying to equal 7 and since 7 is prime our only choice is 1 * 7

So for we have

|dw:1367490644080:dw|

We also know that the signs have to be different or every value in would be positive.

Now we just have to look at what values give us the right middle value.

12x * -7 + 6x*1 = -82x
2x*-7 + 1*6x     = -14x + 6x = -8x 

which is the middle value we want

So we've arrived at (2x + 1)(6x - 7)

imtant · Answer

So,the values of x must be 7/6 and -1/2..

hunus · Answer

Yes

anonymous · Answer

p = $14,300

r = 7 1/2%

t = 4
What is it? can soemone help

hunus · Answer

How often is it compounded?

anonymous · Answer

Thats the point i dont know

hunus · Answer

If its not specified it's usually once yearly

anonymous · Answer

it has like 3 answers for it ? nd i cnt get neither of them right ?

hunus · Answer

So just use the equation
$$A=P(1+r)^{t}$$

hunus · Answer

Is 19000 one of them?

anonymous · Answer

no?? these r the answers nd it dnt make no sience                                                         $4.29
$429.00
$4,290.00

hunus · Answer

I don't think any of those answers make any sense if you're looking for money after interest

anonymous · Answer

lolz thats what im sayen ? i dnt get it nd it dnt make no sience