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In circle F, Angle CFD=DFE, mBFA=8x, mAFE=5x+11 and BE and AC are diameters
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find m arc DC
hint : mBFA + mAFE = 180
I still dont get it...im just not good at this section
you're given mBFA and mAFE, right ? plug them in the above equation and gind x first
mBFA + mAFE = 180 8x + 5x+11 = 180 13x + 11 = 180 13x = 169 x = ?
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Would be 13?
right, now use that to find m arc DC
we first find mBFA mBFA = 8x = 8*13 = 104
yeah
but, mEFC and mBFA are equal cuz both are vertical angles
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okay
so mEFC = 104 also, since CFD and DFE are equal, m arc CD = mEFC/2 = 104/2 = ?
52?
it has to be !
Thank you!
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yw !
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