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x(2x-3)(4x+1)=0
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solve for x?
find the solutions
Ok, so \[x=0\] \[(2x - 3) = 0\] \[(4x - 1) = 0\] You solve for x in all of them.
omg. thanks so much!
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what about 27x^3+8y^3 factored?
I can help with that, but for future reference you should post new questions. \[27x^3+8y^3\] For an answer I got, \[(3x+2y)(9x^2-6xy+4y^2)\]
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