Question

could anyone help me with the half angle formulas for tan.

i have tan(5pi)/4

i can get everything plugged into the formula but i am having trouble simplify


@precal

Answer 1

Do u want to find the value of tan(5pi)/4?

Answer 2

@bfinn4

Answer 3

yes the exact value

Answer 4

i am having trouble simplify all the radical stuff..and i dont have a way to type a radical into this web site so i dont know how to show you my work?

Answer 5

oops i typed that woring i want the value of tan(5pi)/8

Answer 6

or tan [((5pi)/4)/2]

Answer 7

`\(sqrt{}\)` u can use this to type radicals.

Answer 8

\[\tan\theta=\frac{2tan(\frac{\theta}{2})}{1-tan^2(\frac{\theta}{2})}\]

Answer 9

\[\frac{\theta}{2}=\frac{5\pi}{8}\]
\[\theta=\frac{5\pi}{4}\]
plugging this in the formula gives u
\[\tan\frac{5\pi}{4}=\frac{2tan\frac{5\pi}{8}}{1-tan^2\frac{5\pi}{8}}\]
\[\pi=180\]
so
\[\frac{5\pi}{4}=225\]
do u knw the value of tan225?

Answer 10

1

Answer 11

yup good:)

Answer 12

so \[\tan\frac{5\pi}{4}=1\].
\[1=\frac{2tan\frac{5\pi}{8}}{1-tan^2\frac{5\pi}{8}}\]
Let us assume \[x=\tan\frac{5\pi}{8}\]
\[1=\frac{2x}{1-x^2}\]
\[1-x^2=2x\]
\[x^2+2x-1=0\]
Can u find x?

Answer 13

@bfinn4

Answer 14

i have to go to class but yes i can find x ...i will do it right after geology.

Answer 15

k 5n:)

Answer 16

@ajprincess she did a great job helping you