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Mathematics 16 Online
OpenStudy (anonymous):

Please Help, or Teach me. i miss this lesson today and this was the given assignment. 1.) 2a+b a+4b a-7b ___________ - ____________ - ____________ a^2-3ab+2b^2 a^2-4ab+3b^2 a^2-5ab+6a^2 2.) 6m 2n ____________ - ___________ m^2+5m+6 m^2+6m+9 3.) m+2 m _____ - _____ 3m+15 5m+25 Thanks in Advance

OpenStudy (ajprincess):

r u familiar with factorising?

OpenStudy (anonymous):

yes i am

OpenStudy (ajprincess):

good:) can u factorise a^2-3ab+2b^2?

OpenStudy (anonymous):

is it 2ab^2?

OpenStudy (ajprincess):

Nope:( Can u tell me two factors of 2 such that their sum is -3?

OpenStudy (anonymous):

(x-2)(x-1)?

OpenStudy (ajprincess):

a^2-3ab+2b^2 the factors of 2 whose sum is -3 are -1 nd -2. split the middle term -3ab using this. then u will get a^2-2ab-ab+2b^2 =a(a-2b)-b(a-2b) =(a-2b)(a-b) Is it clear?

OpenStudy (anonymous):

so the factor of the a^2-4ab+3b^2 is -3 -1 also a^2-3ab-ab+3b^2 =a(a-3b)-b(a-3b) =(a-3b)(a-b)?

OpenStudy (anonymous):

a^2-5ab+6a^2 = (a-2)(a-3) i dont know next

OpenStudy (anonymous):

can u help me with any number there, so that i can answer the others by myself.

OpenStudy (ajprincess):

good:) so a^2-3ab+2b^2=(a-2b)(a-b) a^2-4ab+3b^2=(a-3b)(a-b) a^2-5ab+6a^2 = (a-2)(a-3)

OpenStudy (ajprincess):

can u find thw l.c.m of (a-2b)(a-b), (a-3b)(a-b) and (a-2)(a-3)?

OpenStudy (anonymous):

i dont know how.

OpenStudy (anonymous):

may i ask if this is correct a^2-5ab+6a^2 = (a-2)(a-3) because i didnt split it yet

OpenStudy (ajprincess):

nope:( sorry i didnt notice it. if it is a^2-5ab+6b^2, then a^2-5ab+6b^2= (a-2b)(a-3b)

OpenStudy (anonymous):

so is it all right if a^2-3ab+2b^2=(a-1b)(a-2b) a^2-4ab+3b^2=(a-1b)(a-3b) ?

OpenStudy (ajprincess):

yup:)

OpenStudy (anonymous):

ajprincess, can you solve any number there then ill do the rest so that i can follow. because its 2am here and i need to sleep thanks for your help btw

OpenStudy (ajprincess):

is it a^2-5ab+6a^2? or a^2-5ab+6b^2?

OpenStudy (anonymous):

its written a^2-5ab+6a^2? but i think it b

OpenStudy (ajprincess):

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