Question

Binomial Probability

Answer 1

\[P(x)=_{n}C _{x}P ^{x}(1-P)^{n-x}\]
was the equation i was given.

Answer 2

its simple... if p=0.35 given you can have q=1-p = 0.65

now its \[\sum_{0}^{4} nCx q^x p^(n-x)\] n is 11 and x is form 0 to 4 sum them all.. Hope u understood

Answer 3

so i write it like \[_{11}C _{0}(0.35)^{0}(1-0.35)^{11-0}\]

Answer 4

yes... you have to find those for 0,1,2,3,4 and you have to sum them all

Answer 5

understood?

Answer 6

ok i'll give that a shot.