Question

Solve this proportion... what is the value of x?

Answer 1

\[\frac{ x }{ x ^{2} - 2 } = \frac{ 2 }{ 3x + 4 }\]

Answer 2

@jim_thompson5910

Answer 3

@campbell_st

Answer 4

\[\large \frac{ x }{ x ^{2} - 2 } = \frac{ 2 }{ 3x + 4 }\]


\[\large x(3x + 4) = 2(x ^{2} - 2)\]


\[\large 3x^2 + 4x = 2x^{2} - 4\]


\[\large 3x^2 + 4x - 2x^{2} + 4 = 0\]


\[\large x^2 + 4x + 4 = 0\]


\[\large (x+2)^2 = 0\]


\[\large x = ?\]

Answer 5

- 2 ?

Answer 6

good