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Chord AC = 30 and OB = 8 below. What is the length of the radius in circle O?
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we see that OB is perpendicular to AC (Since OBC = 90). So if a perpendicular line is drawn from centre to a chord AC, what would probably happen to chord AC ?
haha nope. The theorem is - "A perpendicular line drawn from the centre to any chord will BISECT the chord". Hence chord AC gets bisected. So basically B becomes mid point of AC, Hence AC = AB = 15 cm. So AB = 15 and OB = 8. all u now have to do is use the pythagoras theorem to find the radius,.
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