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2a+2 ----- a²-1 Help?
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\[\frac{ 2a+2 }{ a²-1 }\]
start with \[\frac{2(a+1)}{(a+1)(a-1)}\] and then cancel
leaves you with \[\frac{2}{a-1}\]
Can u simlify more?
not after you write \(\frac{2}{a-1}\) that is the best you can do
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Are they also asking for the restrictions on that? If so, that is when the division would be undefined. Does that make sense?
Oh, ok. Thanks!!!
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