If a chord of circle with radius 5 cm subtends a right angle at the centre , then length of chord is
|dw:1367571323640:dw|
use the pythagorean theorem to get x
x^2 = 5^2 + 5^2 solve for x
@aadhiswaran
Imagine it like tetherball with rope length l and the furthest away from the center pole it can get is 5cm: |dw:1367571015624:dw| When the ball is furthest away from the pole, that means it makes a 45 degree angle |dw:1367571250520:dw| If you increase the angle, you'll get close to the pole, and if you decrease the angle, it'll also bring you closer to the pole. Since it's a 45 degree/45 degree/90 degree triangle, you get |dw:1367571419627:dw| Just use the Pythagorean Theorem to solve for l \[l = \sqrt{5^2+5^2}\ = \sqrt{50}\ = 5\sqrt{2} \ \]
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