Question

The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. Find the measure of the smaller angle.

A. 18°
B. 36°
C. 54°
D. 58°

Answer 1

Let the angles be a and b.
a+b=90( sum of complementary angles is 90)
a+b-(a-b)=72
90-a+b=72
b-a=72-90
b-a=-18
a-b=18
a+b=90
Does that help?

Answer 2

This helps me a lot by the way.. :)

Answer 3

LOL

Answer 4

@waterineyes reported for medal hounding! lol

Answer 5

he he :p

Answer 6

**whichever post of aj you see

Answer 7

now don't tell me you are not typing :P

Answer 8

good idea! ;)

Answer 9

well, no mods online, we can spam this question as much as we want :P

Answer 10

mods can see deleted comments.. -_-

Answer 11

i would look like a fool talking to myself xD

Answer 12

-_-

Answer 13

damn!

Answer 14

Let me tell you a fact., that 4th 'offline' person viewing this post is actually a moderator!

Answer 15

read my previous comment ;)

Answer 16

its evening here.

Answer 17

i know that its evening for all 4 of us

Answer 18

yup.

Answer 19

now, this is getting lamer :P

Answer 20

damn i missed your last comment :P

Answer 21

you cracking this joke since your OS birth.

Answer 22

that w is of lower caps , and name is in bold

Answer 23

i never said you are bad, at all

Answer 24

lets get back to helping.