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Mathematics 6 Online
OpenStudy (anonymous):

find limit lim x^3 +12x^2 - 5x / x->0 5x

OpenStudy (anonymous):

factor out x from the numerator, what you get ?

OpenStudy (anonymous):

x( x^2 -12 x -5)

OpenStudy (anonymous):

+12 x ,right ? and now you can cancel out this 'x' from numerator with the 'x' from denominator because as x-->0, x \(\ne\)0

OpenStudy (anonymous):

Awesome! Thank you!

OpenStudy (anonymous):

and then you can directly put x=5.... welcome ^_^

OpenStudy (anonymous):

sorry, x=0

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