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find limit lim x^3 +12x^2 - 5x / x->0 5x
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factor out x from the numerator, what you get ?
x( x^2 -12 x -5)
+12 x ,right ? and now you can cancel out this 'x' from numerator with the 'x' from denominator because as x-->0, x \(\ne\)0
Awesome! Thank you!
and then you can directly put x=5.... welcome ^_^
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sorry, x=0
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