Question

Help me please..

Answer 1

\[\frac{ 2a ^{2}-4a+2 }{ 3a ^{2}-3 }\]

Answer 2

take out 3 common in the denominator then 3(a^2 - 1) = 3(a+1)(a-1)

in the numerator take out 2 in common 2(a^1 -2a +1 ) = 2(a+1)^2

cancel (a+1) in the numerator and denominator, you'll get

2(a+1)/3(a-1) hope u understood