Find the first four iterates of the function f(z)=z^2+2+2i with an initial value ofzsub0=2+2i
2+10i,-94+42i,7074-7894i, -12273758-111684310i
2+10i,-94+42i,7074-7894i, -12273758+2i
2+2i,2+42i,2-7894i
an explanation would help too
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OpenStudy (anonymous):
@Hope_nicole
OpenStudy (anonymous):
oh i just did this stuff :D
OpenStudy (anonymous):
really?! @Hope_nicole help me!! do you do connections?
OpenStudy (anonymous):
yeah!
OpenStudy (anonymous):
ahh @Hope_nicole help me!! do you have bakhos?
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OpenStudy (anonymous):
okay so! the zsub0 means that it is the first iterate in it. so you plug that into the f(z)=z^2+2+2i and then once you get that answer you use that as the next iterate, and then you plug that in to find the second one
OpenStudy (anonymous):
thanks @Hope_nicole
OpenStudy (anonymous):
does that help :D DID I JUST HELP SOMEONE WITH PRECALC!
OpenStudy (anonymous):
yes kinda @Hope_nicole
OpenStudy (anonymous):
how can i make it make more sense? lol
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OpenStudy (anonymous):
okay, so your first iterate will be the 2+2i. so you would take that and plug it in for z.
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
can you help me with all of the practice though?
OpenStudy (anonymous):
sure!
OpenStudy (anonymous):
what's your last name so I can web mail you
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