Question

Determine if the function is even, odd, or neither.
f(x) = x^3 0< x < 2
I thought this would be odd since x is raised to an odd power but, according to the book, it's neither.
Please explain and thank you

Answer 1

the range of values does not allow for a negative number, so the graph has only one side. Hence it is neither

Answer 2

domain is 0<x<2 ,x^3 is positive in this domain
we can not think of negative value ,hence we can not think of odd or even value.
there it is neither even or odd.

Answer 3

y-1=2\[\left| x \right|\]

Answer 4

vertex is(0,1)