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Determine if the function is even, odd, or neither. f(x) = x^3 0< x < 2 I thought this would be odd since x is raised to an odd power but, according to the book, it's neither. Please explain and thank you
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the range of values does not allow for a negative number, so the graph has only one side. Hence it is neither
domain is 0<x<2 ,x^3 is positive in this domain we can not think of negative value ,hence we can not think of odd or even value. there it is neither even or odd.
y-1=2\[\left| x \right|\]|dw:1367610684819:dw|
vertex is(0,1)
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