Question

An investment is worth $3518 in 1995. By 2000 it has grown to $5553. Let y be the value of the investment in the year x, where x = 0 represents 1995. Write a linear equation that models the value of the investment in the year x.

A. y = -407x + 7588

B. y = 1/407 x + 3518

C. y = -407x + 3518

D. y = 407x + 3518

Answer 1

so, in year 1995, it was $3518, and in 2000, 5 years later, $5553, how much has it grown?

Answer 2

so the y intercept of the line is when x = 0... $3518

and after 5 years you have $5553

so to find the slope its m = (5553 - 3518)/(5 - 0)

the sline will be

y = mx + 3518

Answer 3

so is it D @campbell_st

Answer 4

looks like it

Answer 5

ok thank you so much for your help

Answer 6

you too @jdoe0001

Answer 7

yw