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OpenStudy (anonymous):
factor completely 4x^2+4x+1
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OpenStudy (anonymous):
it will be x?
OpenStudy (anonymous):
multiplying by it reciprocal?
OpenStudy (anonymous):
if take out the 2, you get : (2x+1)(2x+1) (2x+1)^2 This is the long approach, but its good to learn
OpenStudy (anonymous):
ok
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