On a road trip you and your family stop a truck stop to take a break and to let your puppy Fido stretch. You notice that they have a triangular dog park that is fenced in on two sides. The third side of the field is formed by a creek. If the fences measure 150 feet and 98 feet, and the side along the creek is 172 feet, what are the measures of the angles made by the dog park?

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Question

On a road trip you and your family stop a truck stop to take a break and to let your puppy Fido stretch. You notice that they have a triangular dog park that is fenced in on two sides. The third side of the field is formed by a creek. If the fences measure 150 feet and 98 feet, and the side along the creek is 172 feet, what are the measures of the angles made by the dog park?

http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/b/assessments/R-LawsofSinesandLawofCosinesQuiz/Geometry_8.4_Quiz_FINAL_29q.png

anonymous · Answer

@RadEn

raden · Answer

use the cosine rule :
|dw:1367658839969:dw|
cosY = (DY^2 + YG^2 - DG^2)/(2 DY DG)
cosY = (150^2 + 98^2 - 172^2)/(2 * 150 * 98)

simplipy the calculations above, then to get the measure of angle Y take the cos^-1(....)