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Solve these over the domain 0≤a≤2pi: 3cos^2a-5cosa-1=3sin^2a and 1/cos^2a+1-3tan^2a=0 I'm not sure what to do for either of these questions, can someone please help?
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umm i think graph it
between that interval
oh nvm
Don't graph anything. Hint: \(\sin^{2}(x) = 1 - \cos^{2}(x)\)
do it like quadratic
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they just want the solution to be in that interval
Ok so like 3cos^2a-5cosa-1=3(1-cos^2(a))?
ya and then just put it on 1 side and finish like ud solve a quadratice equation
Like 3cos^2a-5cosa-1-3-3cos^2(a)=0?
ya but +3cos^2
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3cos^2a-5cosa-1-3+3cos^2(a)=0? 6cos^2a-5cosa-4=0
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