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Make 'n' the subject of the formula:
s=(2a/3)sq.rt (b2-n2), where 0
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i don't really understand the point
u want just solve the eqn
just a correction its (b sq. - n sq.) and yes I just want to solve the equation. Thnx in advance :)
i think something wrong with the queastion
\[s=\frac{ 2a }{ 3 }\sqrt{b ^{2}-n ^{2}} \]
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s^2= (4a/9)b^2 -n^2 (9/4a)a^2=b^2 -n^2 s^2=(9/4a^3)-n^2=b^2
so u now just take the cubic eqn
I still can't figure it out :(
sorry i would help u if i know
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