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If h(x) = −5x − 10, find h(−2). −20 1.6 −1 0
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h(-2) = -5(-2) - 10 = ?
10-10 = 0
\[h \left( x \right)=-5x-10\] put x=-2 \[h \left( -2 \right)=-5\times-2-10=10-10=0\]
If h(x) = −5x − 10, find h(−2). --SUBSTITUTE h(-2) for x variables. h(-2) = −5(-2) − 10 h(-2) = 10 - 10 h(-2) = 0
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