Question

How do you solve this in radical form?

Answer 1

3x^2 + 2x -7= 0

Answer 2

use quadratic formula.

Answer 3

Compare your quadratic equation with \(ax^2+bx+c=0\)
find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\]
then the two roots of x are:
\(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)