Question

how do I solve this using perfect square
3x^2-6x=17 I need the answer with work

Answer 1

are you familiar with completing the square?

Answer 2

yes

Answer 3

am I wrong or you'd need the quadratic formula for that?

Answer 4

I need both

Answer 5

ax^2 + bx + c = 0

turn that into: a(x+d)^2 + e = 0

where

d = b/(2a)
and
e = c - (b^2)/(4a)

Answer 6

\(
3x^2-6x-17=0
\), and plug the values in the quadratic formula :|

Answer 7

that doesn't allow him to solve for perfect squares

Answer 8

ok, I see the difference