i am trying to find the area in yds of a triangle with a base of 1 4/5 and height of 5/8 is
a= (1/2) (1 4/5)(5/8)
a=(1/2)(9/5)(5/8)
a=45/80
right and where do i go from there and how

Question

i am trying to find the area in yds of a triangle with a base of 1 4/5 and height of 5/8  is 
a= (1/2) (1 4/5)(5/8)
a=(1/2)(9/5)(5/8)
a=45/80
right and where do i go from there and how

zzr0ck3r · Answer

area of triangle = 1/2 * b * h
you have b = 9/5 and h = 5/8
can you solve?

anonymous · Answer

Thats where i am stuck it does not make sense to me

zzr0ck3r · Answer

area = (1/2)*b*h    b = 9/5    h = 5/8

zzr0ck3r · Answer

so
area = (1/2)*(9/5)*(5/8) = (1*9*5)/(2*5*8) = 45/?

anonymous · Answer

80

anonymous · Answer

Where did you get these values from?

a= (1/2) (1 4/5)(5/8)
a=(1/2)(9/5)(5/8)
a=45/80

anonymous · Answer

are they wrong

anonymous · Answer

Ignore me.

I see what you did now...

yes, the answer is 45/80 = .5625 = 9/16

anonymous · Answer

thank you i was forgetting to simplify

anonymous · Answer

No problem!

And thank you!  :-)