Question

compute the limits

Answer 1

\[\frac{ x^3-x }{ x^2-x-2 }\]
all i have to do is to divided by x^2 and x^3 for top and bottom?

Answer 2

factor both. Should fall out nicely

Answer 3

\[\frac{ x(x^2-1) }{ (x-2)(x+1) }\]

Answer 4

@Mertsj ?

Answer 5

\[\frac{x(x-1)(x+1)}{(x-2)(x+1)}\]

Answer 6

\[\frac{x(x-1)}{x-2}\]

Answer 7

What is x approaching?

Answer 8

x approaches ZERO

Answer 9

Then the limit is 0. Look at the numerator

Answer 10

Thank you very much! I understand

Answer 11

yw