A particle moves along the x-axis with velocity given by v(t)=3t^2 + 6t for time t or equal 0. If the particle is at position x = 2 at time = 0, what is the position of the particle at time t = 1?

Question

A particle moves along the x-axis with velocity given by v(t)=3t^2 + 6t for time t > or equal 0. If the particle is at position x = 2 at time = 0, what is the position of the particle at time t = 1?

anonymous · Answer

I forgot how to do this, can you help me please? :)

anonymous · Answer

@agent0smith

agent0smith · Answer

v(t)=3t^2 + 6t

Integrate it to find x(t).

Use x = 2 at t = 0 to find the C.

Then plug in t = 1 to find x(1).

anonymous · Answer

k thx, can you help me with another problem? ^^