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Mathematics 15 Online
OpenStudy (anonymous):

y1 = /x+2/-3

OpenStudy (anonymous):

What?

OpenStudy (anonymous):

can u pls rewrite your q'

OpenStudy (anonymous):

\[y_1 = \frac{x+2}{-3}\]

OpenStudy (anonymous):

Evaluate the polynomial 6x - y for x = - 3 and y = 2. A. 15 B. –20 C. 4 D. –16

OpenStudy (anonymous):

Don't know..

OpenStudy (anonymous):

just wait

OpenStudy (anonymous):

you just subsitute the x and y value in the equation

OpenStudy (anonymous):

Just plug in those values, x = -3 and y = 2 there in your expression: \[6x -y \implies 6(-3) - (2) \implies -18 -2 = ???\]

OpenStudy (anonymous):

Thank you both ;)

OpenStudy (anonymous):

What you got as your answer??

OpenStudy (anonymous):

-20

OpenStudy (anonymous):

Good...

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