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OpenStudy (anonymous):
How to get the derivative of f(x)=(cosecx)^2 ?
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geerky42 (geerky42):
Chain rule. \[\dfrac{d}{dx}f(g(x)) = f'(g(x))\cdot g'(x)\]In this case, f(x) = x², g(x) = cosecx
OpenStudy (raden):
do u know the derivative of cosec(x) ?
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