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Mathematics 15 Online
OpenStudy (anonymous):

How to get the derivative of f(x)=(cosecx)^2 ?

geerky42 (geerky42):

Chain rule. \[\dfrac{d}{dx}f(g(x)) = f'(g(x))\cdot g'(x)\]In this case, f(x) = x², g(x) = cosecx

OpenStudy (raden):

do u know the derivative of cosec(x) ?

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