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Algebra
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7-4i over 2+3i
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Always multiply by the conjugate of denominator when you see these problems.
\[\frac{7-4i}{2+3i}\times \frac{2-3i}{2-3i}\]
\[\frac{14-21i-8i+12i^2}{4-9i^2}\] Using \(i^2=-1\), \[\frac{14-21i-8i+12(-1)}{4-9(-1)} \] Solve
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