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Algebra 13 Online
OpenStudy (anonymous):

7-4i over 2+3i

sam (.sam.):

Always multiply by the conjugate of denominator when you see these problems.

sam (.sam.):

\[\frac{7-4i}{2+3i}\times \frac{2-3i}{2-3i}\]

sam (.sam.):

\[\frac{14-21i-8i+12i^2}{4-9i^2}\] Using \(i^2=-1\), \[\frac{14-21i-8i+12(-1)}{4-9(-1)} \] Solve

OpenStudy (anonymous):

guys, not to be mean or anything, could any of you answer my question?

OpenStudy (anonymous):

whats your question

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