Question

Urgent! I need someone to help me solve for v in this equation:

Answer 1

\[L=\frac{ v _{c}^{2}\cos \theta sen \theta -v _{c}\cos \theta \sqrt{v _{c}^{2}\sin ^{2}\theta-2g(h _{C}-h _{D})} }{ g }\]

Answer 2

did you try wolfram?

Answer 3

E=MCVagina...Therefore V=E/MC

Answer 4

Already solved it thank you :)