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Solve each equation by completing the square Quick! Will give medal and fan
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@satellite73
@bahrom7893 @ganeshie8
\[x^2+2x+5=0\]
or \[x^2+2x-5=0\]
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the subtact one sorry
ok then add 5 to both sides and write \[x^2+2x=5\]
-1-sqrt6, -1+sqrt6
then half of 2 is 1, and \(1^2=1\) so the next step is to write \[(x+1)^2=5+1\] or \[(x+1)^2=6\]
take the square root of both sides, don't forget the \(\pm\) and write \[x+1=\pm\sqrt6\]
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finally subtract 1 from both sides to get \[x=-1\pm\sqrt 6\]
Okay wait whats the sq root of 6?
@satellite73
i would leave it as that do you need a decimal?
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