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Algebra 15 Online
OpenStudy (anonymous):

can someone help me to prove cot^2x=(cosx)/(sinx tanx)

OpenStudy (anonymous):

I am not sure which approach must be taken but right away I see that the right side is: \frac{ cosx }{ sinx }* \frac{ 1 }{ tanx } which is cotx*cotx

OpenStudy (anonymous):

thank you!!

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