Question

factor!!!!
x^8-1

Answer 1

\[x ^{8}-1=(x ^{4})^{2}-1=(x ^{4}+1)(x ^{4}-1)=(x ^{4}+1)((x ^{2})^{2}-1)=(x ^{4}+1)(x ^{2}-1)(x ^{2}+1)\]

Answer 2

The answer :
\[(x ^{4}+1)(x ^{2}-1)(x ^{2}+1)\]

Answer 3

Awesome thanks