Question

Find the angle between plane VBC and plane VCD.
[VA=VB=VC=VD=10, ABCD is a square with the length of a side=8]

Answer 1

if thats a pyramid, then there is no plan AVCD

Answer 2

find this face height first

Answer 3

VCD...I am sorry:)

Answer 4

\[tan(\alpha)=\frac h4\]
and by the pythag thrm we have\[h = \sqrt{10^2-4^2}\]

Answer 5

am i correct? the angle