Question

Calculus Help!

Answer 1

I've never seen an integral in this form. Can someone help me with this please? What's significant about the 1/b ?

Answer 2

it is the average

Answer 3

the length from \(0\) to \(b\) is \(b\) divide the integral by the length of the path to get the average value of the function

Answer 4

in other words, the average value of \(f\) over the interval \([a,b]\) is
\[\frac{1}{b-a}\int_a^b f(x)dx\]

Answer 5

in your example \(a=0\)

Answer 6

Makes sense to me. Thanks! :)

Answer 7

yw