Question

What is the quotient of a=4/8b ./. a2-2a-24/b3?

(a+4)(a-6)/8b2, b ≠ 0

b2/8(a-6), a ≠‚ −4, 6 and b ≠ 0

(a-6)/8b2,b ≠ 0

b2/8(a+4), a ≠ 6 and b ≠ 0

Answer 1

\[a= \frac{ 4 }{ 8b }+a^{2}-2a-\frac{ 24 }{ b ^{3} }\]
Is this the beginning thing?

Answer 2

no

Answer 3

\[a=\frac{ \frac{ 4 }{ 8b } }{ \frac{ a^{2}-2a-24 }{ b^{3} } }\]
Like this?