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Mathematics 21 Online
OpenStudy (anonymous):

x = sqrt 4x + 12

OpenStudy (diyadiya):

What do you want to find?

OpenStudy (anonymous):

I want to solve the equation.

OpenStudy (diyadiya):

\[x=\sqrt{4x} + 12\] or \[x= \sqrt{4}x +12\]

OpenStudy (diyadiya):

is it the second one or first one? Anyways, sqrt of 4 is 2

OpenStudy (anonymous):

I ended up with 6 and -2 somehow.

OpenStudy (diyadiya):

try to isolate and find x

OpenStudy (diyadiya):

If its the second eqation then, x=2x+12 -2x+x=12 x=-12 x=-2x+12 2x+x=12 x=4

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