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Find the range of the quadratic function. f(x) = (x + 8)^2 - 7 A. [-7, ∞) B. (-∞, -8] C. [-8, ∞) D. (-∞, -7]
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The answer i picked was A.
It's a parabola opening `upward`. So it will increase towards positive infinity. But where is the vertex located? The smallest value y can take? Well it's normally at y=0, but our function has been shifted `downward 7 units`. So our smallest y value is -7, which no boundary on the upper. Yes, good job ninja girl! c:
thanks @zepdrix
@zepdrix is right @Luis_Rivera x=0 ?? it is not important to find the range
thanks @julian25 :-)
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