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x2+5x=14
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x^2 +5x -14 = 0 [(-b \pm \sqrt{b ^{2}-4*a*c})/2*a\] 1 = a 5 = b 14 = c
i dont get it thoe.
x^2+5x=14 factor out an x x(x+5) =14 do you know how to solve that.
okay it will be x=9 right
or am i wrong.?
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and x = 14
so how could i do it.?
x^2+5x=14 x(x+5) = 14 x = 14 and x + 5 = 14 x = 14-5 x = 9
so i was right.
yes, but you also have to have x = 14. there are two solutions.
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ooh okay so thats not it.? because i subracted 14 and 5.
\[x^ 2+5x- 14= 0 \\ x^ 2-2x + 7x -14= 0 \\ x (x + 7) -2 (x + 7 ) = 0\\ (x + 7) (x +2) \\\\ x = 7, \ \ \ x = -2\]
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