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Mathematics
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Solve each equation. Show work! Medal will be rewarded for help! :D
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\[8^{2x} = \frac{ 1 }{ 16 }\]
\[25^{2x} = 125^{x+2}\]
The first one is suppose to be \[8^{x - 2}\]
You should post only 1 at a time. Otherwise it get confusing. can you change both 8 and 16 to the form 2^x where x is some number ?
the trick is get a common base. 2*2*2 = 8 so 2^3 = 8
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what is x so that 2^x = 16
It's 4
@Firejay5 first take 2 question |dw:1367929622696:dw|
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