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OpenStudy (anonymous):
What values for Θ(0<=Θ<= 2pi) satisfy this equation? 3sin Θ=sin Θ -1
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OpenStudy (loser66):
3sin theta -sin theta = -1 ---> 2 sin theta = -1 ---> sin theta = -1/2 . solve for theta then.
OpenStudy (anonymous):
I think I got it, is it 2pi/3, and 4pi/3?
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