HOW ON EARTH DO I DO THIS???
Ofcourse you cant do it on MOON
@AravindG
Are all these 4 pics referring to same question?
yes
I see 5 questions .Which one do you have doubt on ?
all of them. they literally make no sense. this whole time i thought it was one problem. it wan't set up correctly in the word doc format
1. root(27)=root(3*9)
root(3*9)=root(3) *root (9)
I hope you can do it after that
should i plug the roots into the calc?
@AravindG
please!!!!!!!!!!!!:((((((((((((((((((((((((((
nope for example \[\sqrt{2}x-\sqrt{8} \times 3=\sqrt{2}x-\sqrt{4 \times 2} \times 3 =\sqrt{2}x-2\sqrt{2} \times 3\] \[=\sqrt{2} \times (x-6)\]
This is how to do these type of problems
i just need help this makes no sense
@Best_Mathematician
@Aperogalics
@Chooch146
@InsanelyChaotic how can i help u ????????
With the problem listed above please. it makes no sense and i just want to cry.
don't cry first of all :) let us solve
first question |dw:1367947608900:dw| in such type of questions we have to take common now second part can be factorise so |dw:1367947718184:dw| but in square root if a no. comes twice that is a pair of two then it comes out and only one term remains i.e.|dw:1367947798491:dw| so back to question |dw:1367947833712:dw| got it if yes then tell me i will proceed to second :)
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