Question

Divide. 4u^2 - 6u/ 2u

A. 4u - 6/ 2

B. 4u - 6

C. 2u - 3/ 2

D. 2u - 3

Answer 1

is ur question this?
\[\frac{4u^2-6u}{2u}\]

Answer 2

yess

Answer 3

???????

Answer 4

can you just tell me you dont have to give big explanation

Answer 5

k:)
\[\frac{4u^2-6u}{2u}\]
\[=\frac{4u^2}{2u}-\frac{6u}{2u}\]
\[=\frac{2u*2u}{2u}-\frac{3*2u}{2u}\]\[=\frac{2u(2u-3)}{2u}\]
Cancel any common factorss nd simplify.:)
Does tht help? @Tcookie009

Answer 6

wich one is it

Answer 7

what is common to both numerator and denominator?

Answer 8

can you just tell me and ill give you three medals

Answer 9

I am really sorry i am afraid i cannot giv u the direct answer and I am nt trying to help u for the medals.:)

Answer 10

wich one are the wrrong ones

Answer 11

can u pls tell me what u see in both numerator and denominator of this fraction?
\[\frac{2u(2u-3)}{2u}\]